Kellybelly - I made this post before about the chemistry of mixing sodium bicarb and ascorbic acid. One thing I didn't note was that in order to get the reaction to occur, it needs to be done in a solvent (water), but then it is necessarily diluted and needs to be dried, which is probably beyond what most of us can achieve at home. I guess when you m ix them dry, the reaction theoretically occurs in your belly, but with the pH being so low there, I amnot sure how it would proceed or if it would. Hmm, I should look into this further.
This is the run down on the correct ratios from the chemical standpoint though.
The ratio is one to one, but you must do it based upon molecular weight, as it is a molar ratio you are attempting to achieve.
Thus, you would use one mole of ascorbic acid to one mole of sodium bicarbonate.
Molecular weight NaHCO3 (sodium bicarb) = 84. g/mol
Molecular weight C6H8O6 (ascorbic acid) = 176.13 g/mol
To make one mole of sodium ascorbate, you would use 84 grams of sodium bicarb and 176 grams of the acid, for a total of 260.13 grams. The reaction yields 1 mole of sodium ascorbate, one mole of water (18 grams), and one mole of carbon dioxide (44 grams), so your total sodium ascorbate would be 198.13 grams.
So, if you were trying to make, say, a 100 gram solution, you would use approximately 32.3 grams sodium bicarb and 67.7 grams of ascorbic acid. (which is close to the 2:1 ratio mentioned by PP) The densities of the two components differs significantly enough that using simply a dry measuring system (instead of weights) would yield an inexact ratio unless you did the proper calculations and made corrections for that difference
This is the run down on the correct ratios from the chemical standpoint though.
The ratio is one to one, but you must do it based upon molecular weight, as it is a molar ratio you are attempting to achieve.
Thus, you would use one mole of ascorbic acid to one mole of sodium bicarbonate.
Molecular weight NaHCO3 (sodium bicarb) = 84. g/mol
Molecular weight C6H8O6 (ascorbic acid) = 176.13 g/mol
To make one mole of sodium ascorbate, you would use 84 grams of sodium bicarb and 176 grams of the acid, for a total of 260.13 grams. The reaction yields 1 mole of sodium ascorbate, one mole of water (18 grams), and one mole of carbon dioxide (44 grams), so your total sodium ascorbate would be 198.13 grams.
So, if you were trying to make, say, a 100 gram solution, you would use approximately 32.3 grams sodium bicarb and 67.7 grams of ascorbic acid. (which is close to the 2:1 ratio mentioned by PP) The densities of the two components differs significantly enough that using simply a dry measuring system (instead of weights) would yield an inexact ratio unless you did the proper calculations and made corrections for that difference





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Cool info.





Maybe some resources that would be considred reliable by establishment types?
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